1
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A body moves along a circular path of diameter $30\ \text{cm}$. It starts from one end of diameter, moves along the circular path and reaches the other end of diameter in 3 second. The angular speed of the body in radian per second is
A
$\dfrac{\pi}{5}$
B
$\dfrac{\pi}{4}$
C
$\dfrac{\pi}{3}$
D
$\dfrac{\pi}{2}$
2
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A particle is moving with constant angular acceleration $4\,\text{rad/s}^2$ in circular path. At what time the magnitudes of its tangential acceleration and centripetal acceleration will be equal ?
A
$0.2$ s
B
$0.4$ s
C
$0.5$ s
D
$0.6$ s
3
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A particle describes a horizontal circle of radius 'r' in conical funnel with smooth inner surface with a speed of $0.5$ m/s. The height of the plane of the circle from the vertex of the funnel is (acceleration due to gravity, $g = 10\,\text{m/s}^2$)
A
$1.5$ cm
B
$2.5$ cm
C
$3.5$ cm
D
$0.5$ cm
4
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
A particle at rest starts moving with constant angular acceleration '$\alpha$' in a circular path of radius 'r'. At certain instant, the magnitude of centripetal acceleration is $\left(\dfrac{1}{3}\right)^{rd}$ the tangential acceleration. The relation between linear speed (V) and angular acceleration ($\alpha$) is
A
$V = \dfrac{r\alpha}{3}$
B
$V = \alpha\sqrt{\dfrac{r}{2}}$
C
$V = r\sqrt{\dfrac{\alpha}{3}}$
D
$V = \sqrt{\dfrac{\alpha r}{3}}$

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