1
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

For a particle moving in a circle with constant angular speed, which of the following statements is 'false'?

A
The velocity vector is tangent to the circle.
B
The acceleration vector is tangent to the circle.
C
The velocity and acceleration vectors are perpendicular to each other.
D
The acceleration vector points to the centre of the circle.
2
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A particle performing uniform circular motion of radius $\frac{\pi}{2} \mathrm{~m}$ makes $x$ revolutions in time $t$. Its tangential velocity is

A
$\frac{x}{\pi t}$
B
$\frac{\pi^2}{x t}$
C
$\frac{\pi^2 x}{t}$
D
$\frac{\pi x}{t}$
3
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A weightless thread can bear tension up to 3.7 kg wt. A stone of mass 500 gram is tied to it and revolved in circular path of radius 4 m in vertical plane. Maximum angular velocity of the stone will be (acceleration due to gravity, $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ )

A
$16 \mathrm{rad} / \mathrm{s}$
B
$4 \mathrm{rad} / \mathrm{s}$
C
$2 \mathrm{rad} / \mathrm{s}$
D
$8 \mathrm{rad} / \mathrm{s}$
4
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The linear speed of a particle at the equator of the earth due to its spin motion is ' V '. The linear speed of the particle at latitude $30^{\circ}$ is

$$\left[\begin{array}{l} \sin 30^{\circ}=\cos 60^{\circ}=1 / 2 \\ \cos 30^{\circ}=\sin 60^{\circ}=\sqrt{3} / 2 \end{array}\right]$$

A
$\frac{\mathrm{V}}{\sqrt{2}}$
B
$\frac{\mathrm{V}}{2}$
C
$\frac{\sqrt{3}}{2} \mathrm{v}$
D
$\mathrm{V}$
MHT CET Subjects
EXAM MAP