MHT CET 2024 16th May Morning Shift | Circular Motion Question 4 | Physics

A particle starting from rest moves along the circumference of a circle of radius ' $r$ ' with angular acceleration ' $\alpha$ '. The magnitude of the average velocity in time it completes the small angular displacement ' $\theta$ ' is

$\frac{r^2}{2 \alpha \theta}$

$\frac{\mathrm{r}}{2 \alpha \theta}$

$\frac{\mathrm{r} \alpha \theta}{2}$

$\frac{\mathrm{r}}{\sqrt{2}} \sqrt{\alpha \theta}$

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

A particle is moving in a circle with uniform speed. It has constant

velocity.

acceleration.

kinetic energy.

displacement.

MHT CET 2024 11th May Evening Shift

MCQ (Single Correct Answer)

-0

A particle of mass ' $m$ ' is performing uniform circular motion along a circular path of radius ' $r$ '. Its angular momentum about the axis passing through the centre and perpendicular to the plane is ' $L$ '. The kinetic energy of the particle is

$\frac{L^2}{2 Mr^2}$

$\frac{2 \mathrm{~L}^2}{\mathrm{mr}^2}$

$\frac{\mathrm{L}^2}{\mathrm{mr}^2}$

$\frac{2 \mathrm{~L}^2}{3 \mathrm{mr}^2}$

MHT CET 2024 10th May Evening Shift

MCQ (Single Correct Answer)

-0

A particle of mass ' $m$ ' performs uniform circular motion of radius ' $r$ ' with linear speed ' $v$ ' under the application of force ' $F$ '. If ' $m$ ', ' $v$ ' and $' \mathrm{r}$ ' are all increased by $20 \%$ the necessary change in force required to maintain the particle in uniform circular motion, is

$12 \%$

$44 \%$

$14 \%$

$144 \%$

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