MHT CET 2021 21th September Morning Shift | Circular Motion Question 61 | Physics

A particle moves in a circular orbit of radius '$$r$$' under a central attractive force, $$F=-\frac{k}{r}$$, where $$\mathrm{k}$$ is a constant. The periodic time of its motion is proportional to

$$r^{\frac{1}{2}}$$

$$\mathrm{r}^{\frac{2}{3}}$$

$$r$$

$$r^{\frac{3}{2}}$$

MHT CET 2021 20th September Evening Shift

MCQ (Single Correct Answer)

-0

A particle at rest starts moving with a constant angular acceleration of $$4 \mathrm{~rad} / \mathrm{s}^2$$ in a circular path. At what time the magnitude of its centripetal acceleration and tangential acceleration will be equal?

$$\frac{1}{4} \mathrm{~S}$$

$$\frac{2}{3} \mathrm{~S}$$

$$\frac{1}{2} \mathrm{~S}$$

$$\frac{1}{3} \mathrm{~S}$$

MHT CET 2020 19th October Evening Shift

MCQ (Single Correct Answer)

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A child starts running from rest along a circular track of radius $r$ with constant tangential acceleration a. After time $t$ he feels that slipping of shoes on the ground has started. The coefficient of friction between shoes and the ground is

[g = acceleration due to gravity]

$\frac{\left[a^4 t^4+a^2 r^2\right]^{\frac{1}{2}}}{g r}$

$\frac{\left[a^4 t^4+a^2 r^2\right]}{r g}$

$\frac{\left[a^2 t^2+a^4 r^4\right]}{r g}$

$\frac{\left[a^4 t^4-a^2 r^2\right]^{\frac{1}{2}}}{r g}$

MHT CET 2020 19th October Evening Shift

MCQ (Single Correct Answer)

-0

A body is moving along a circular track of radius 100 m with velocity $20 \mathrm{~m} / \mathrm{s}$. Its tangential acceleration is $3 \mathrm{~m} / \mathrm{s}^2$, then its resultant acceleration will be

$5 \mathrm{~m} / \mathrm{s}^2$

$4 \mathrm{~m} / \mathrm{s}^2$

$2 \mathrm{~m} / \mathrm{s}^2$

$3 \mathrm{~m} / \mathrm{s}^2$

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