MHT CET 2025 21st April Evening Shift | Circular Motion Question 1 | Physics

A simple pendulum oscillates with an angular amplitude $\theta$. If the maximum tension in the string is 4 times the minimum tension then the value of $\theta$ is

$\cos ^{-1}(0.75)$

$\cos ^{-1}(0.5)$

$\sin ^{-1}(0.5)$

$\sin ^{-1}(0.75)$

MHT CET 2025 21st April Evening Shift

MCQ (Single Correct Answer)

-0

A pendulum bob has a speed $4 \mathrm{~m} / \mathrm{s}$ at its lowest position. The pendulum is 1 m long. When the length of the string makes an angle of $60^{\circ}$ with the vertical, the speed of the bob at that position is (acceleration due to gravity, $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$, $\cos 60^{\circ}=0.5$ )

$6 \mathrm{~m} / \mathrm{s}$

$\sqrt{3} \mathrm{~m} / \mathrm{s}$

$\sqrt{6} \mathrm{~m} / \mathrm{s}$

$3 \mathrm{~m} / \mathrm{s}$

MHT CET 2025 20th April Morning Shift

MCQ (Single Correct Answer)

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For a particle moving in a circle with constant angular speed, which of the following statements is 'false'?

The velocity vector is tangent to the circle.

The acceleration vector is tangent to the circle.

The velocity and acceleration vectors are perpendicular to each other.

The acceleration vector points to the centre of the circle.

MHT CET 2025 19th April Evening Shift

MCQ (Single Correct Answer)

-0

A particle performing uniform circular motion of radius $\frac{\pi}{2} \mathrm{~m}$ makes $x$ revolutions in time $t$. Its tangential velocity is

$\frac{x}{\pi t}$

$\frac{\pi^2}{x t}$

$\frac{\pi^2 x}{t}$

$\frac{\pi x}{t}$

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