In the circuit shown, the phase currents are

$$ \begin{aligned} & I_A=572.812+j 50.115 \mathrm{~A} \\ & I_B=-254.525-j 459.175 \mathrm{~A} \\ & I_C=-207.083+j 444.091 \mathrm{~A} \end{aligned} $$

Given that the CTs are ideal with no saturation, and the turns ratio of the Main CT is $300: 5$ and that of the Auxiliary Transformer $(Y n \Delta)$ is $2: 1$ on every phase, the value of $I_{A R}$, rounded off to three decimal places, is

The two-bus power system shown in figure (i) has one alternator supplying a synchronous motor load through a Y-$$\Delta$$ transformer. The positive, negative and zero-sequence diagrams of the system are shown in figures (ii), (iii) and (iv), respectively. All reactances in the sequence diagrams are in p.u. For a bolted line-to-line fault (fault impedance = zero) between phases 'b' and 'c' at bus 1, neglecting all pre-fault currents, the magnitude of the fault current (from phase 'b' to 'c') in p.u. is ____________ (Round off to 2 decimal places).

Suppose $I_A, I_B$ and $I_C$ are a set of unbalanced current phasors in a three-phase system. The phase-B zero-sequence current $I_{B 0}=0.1 \angle 0^0$ p.u. If phase-A current $I_A=1.1 \angle 0^0$ p.u and phase- $C$ current $I_C=\left(1 \angle 120^0+0.1\right)$ p.u., then $I_B$ in p.u is