1
JEE Advanced 2014 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

Match the orbital overlap figures shown in List I with the description given in List II and select the correct answer using the code given below the lists.

JEE Advanced 2014 Paper 2 Offline Chemistry - Chemical Bonding & Molecular Structure Question 8 English

A
P-2, Q-1, R-3, S-4
B
P-4, Q-3, R-1, S-2
C
P-2, Q-3, R-1, S-4
D
P-4, Q-1, R-3, S-2
2
JEE Advanced 2014 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

Different possible thermal decomposition pathways for peroxyesters are shown below. Match each pathway from List I with an appropriate structure from List II and select the correct answer using the code given below the lists.

JEE Advanced 2014 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 39 English 1

JEE Advanced 2014 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 39 English 2

A
P-1, Q-3, R-4, S-2
B
P-2, Q-4, R-3, S-1
C
P-4, Q-1, R-2, S-3
D
P-3, Q-2, R-1, S-4
3
JEE Advanced 2014 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

Match the four starting materials (P, Q, R, S) given in List I with the corresponding reaction schemes (I, II, III, IV) provided in List II and select the correct answer using the code given below the lists.

JEE Advanced 2014 Paper 2 Offline Chemistry - Compounds Containing Nitrogen Question 15 English

A
P-1, Q-4, R-2, S-3
B
P-3, Q-1, R-4, S-2
C
P-3, Q-4, R-2, S-1
D
P-4, Q-1, R-3, S-2
4
JEE Advanced 2014 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1
Let $${z_k}$$ = $$\cos \left( {{{2k\pi } \over {10}}} \right) + i\,\,\sin \left( {{{2k\pi } \over {10}}} \right);\,k = 1,2....,9$$

List-I


P. For each $${z_k}$$ = there exits as $${z_j}$$ such that $${z_k}$$.$${z_j}$$ = 1
Q. There exists a $$k \in \left\{ {1,2,....,9} \right\}$$ such that $${z_1}.z = {z_k}$$ has no solution z in the set of complex numbers
R. $${{\left| {1 - {z_1}} \right|\,\left| {1 - {z_2}} \right|\,....\left| {1 - {z_9}} \right|} \over {10}}$$ equals
S. $$1 - \sum\limits_{k = 1}^9 {\cos \left( {{{2k\pi } \over {10}}} \right)} $$ equals

List-II


1. True
2. False
3. 1
4. 2
A
P = 1, Q = 2, R = 4, S = 3
B
P = 2, Q = 1, R = 3, S = 4
C
P = 1, Q = 2, R = 3, S = 4
D
P =2, Q = 1, R = 4, S = 3
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