1
IIT-JEE 2011 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-1
Which of the following statement(s) is/are correct?
A
If the electric field due to a point charge varies as $${r^{ - 2.5}}$$ instead of $${r^{ - 2}},$$ then the Gauss law will still be valid.
B
The Gauss law can be used to calculate the field distribution around an electric dipole.
C
If the electric field between two point charges is zero somewhere, then the sign of the two charges is the same.
D
The work done by the external force in moving a unit positive charge from point $$A$$ at potential $${V_A}$$ to point $$B$$ at potential $${V_B}$$ is $$\left( {{V_B} - {V_A}} \right).$$
2
IIT-JEE 2011 Paper 2 Offline
MCQ (Single Correct Answer)
+2
-0.5
A wooden block performs $$SHM$$ on a frictionless surface with frequency, $${v_0}.$$ The block carries a charge $$+Q$$ on its surface . If now a uniform electric field $$\overrightarrow E $$ is switched- on as shown, then the $$SHM$$ of the block will be
IIT-JEE 2011 Paper 2 Offline Physics - Simple Harmonic Motion Question 18 English
A
of the same frequency and with shifted mean position.
B
of the same frequency and with the same mean position
C
of changed frequency and with shifted mean position.
D
of changed frequency and with the same mean position.
3
IIT-JEE 2011 Paper 2 Offline
MCQ (Single Correct Answer)
+2
-0.5
Which of the field patterns given below is valid for electric field as well as for magnetic field ?
A
IIT-JEE 2011 Paper 2 Offline Physics - Electrostatics Question 56 English Option 1
B
IIT-JEE 2011 Paper 2 Offline Physics - Electrostatics Question 56 English Option 2
C
IIT-JEE 2011 Paper 2 Offline Physics - Electrostatics Question 56 English Option 3
D
IIT-JEE 2011 Paper 2 Offline Physics - Electrostatics Question 56 English Option 4
4
IIT-JEE 2011 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
A point mass is subjected to two simultaneous sinusoidal displacements in x-direction, $${x_1}\left( t \right) = A\sin \omega t$$ and $${x_2}\left( t \right) = A\sin \left( {\omega t + {{2\pi } \over 3}} \right)$$. Adding a third sinusoidal displacement $${x_3}\left( t \right) = B\sin \left( {\omega t + \phi } \right)$$ brings the mass to a complete rest. The values of B and $$\phi $$ are
A
$$\sqrt 2 A,{{3\pi } \over 4}$$
B
$$A,{{4\pi } \over 3}$$
C
$$\sqrt 3 A,{{5\pi } \over 6}$$
D
$$A,{\pi \over 3}$$
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