1
IIT-JEE 2011 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-1
Which of the following statement(s) is/are correct?
A
If the electric field due to a point charge varies as $${r^{ - 2.5}}$$ instead of $${r^{ - 2}},$$ then the Gauss law will still be valid.
B
The Gauss law can be used to calculate the field distribution around an electric dipole.
C
If the electric field between two point charges is zero somewhere, then the sign of the two charges is the same.
D
The work done by the external force in moving a unit positive charge from point $$A$$ at potential $${V_A}$$ to point $$B$$ at potential $${V_B}$$ is $$\left( {{V_B} - {V_A}} \right).$$
2
IIT-JEE 2011 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

A light ray travelling in glass medium is incident on glass-air interface at an angle of incidence $$\theta$$. The reflected (R) and transmitted (T) intensities, both as function of $$\theta$$, are plotted. The correct sketch is

A
IIT-JEE 2011 Paper 2 Offline Physics - Wave Optics Question 5 English Option 1
B
IIT-JEE 2011 Paper 2 Offline Physics - Wave Optics Question 5 English Option 2
C
IIT-JEE 2011 Paper 2 Offline Physics - Wave Optics Question 5 English Option 3
D
IIT-JEE 2011 Paper 2 Offline Physics - Wave Optics Question 5 English Option 4
3
IIT-JEE 2011 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

A long insulated copper wire is closely wound as a spiral of N turns. The spiral has inner radius a and outer radius b. The spiral lies in the xy-plane and a steady current I flows through the wire. The z-component of the magnetic field at the centre of the spiral is

IIT-JEE 2011 Paper 2 Offline Physics - Magnetism Question 12 English

A
$${{{\mu _0}NI} \over {2(b - a)}}\ln \left( {{b \over a}} \right)$$
B
$${{{\mu _0}NI} \over {2(b - a)}}\ln \left( {{{b + a} \over {b - a}}} \right)$$
C
$${{{\mu _0}NI} \over {2b}}\ln \left( {{b \over a}} \right)$$
D
$${{{\mu _0}NI} \over {2b}}\ln \left( {{{b + a} \over {b - a}}} \right)$$
4
IIT-JEE 2011 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-2

Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only if

IIT-JEE 2011 Paper 2 Offline Physics - Properties of Matter Question 13 English

A
dA < dF
B
dB > dF
C
dA > dF
D
dA + dB = 2dF
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