Statement-1 : Alkali metals dissolves in liquid ammonia to give blue solutions
Statement-2 : Alkali metals in liquid ammonia give solvated species of the type $$\left[\mathrm{M}\left(\mathrm{NH}_{3}\right)_{n}\right]^{+} (\mathrm{M}=$$ alkali metals).
Statement-1 : Glucose gives a reddish-brown precipitate with Fehling's solution.
Statement-2 : Reaction of glucose with Fehling's solution gives $$\mathrm{CuO}$$ and gluconic acid.
Statement-1 : Molecules that are not superimposable on their mirror images are chiral.
Statement-2 : All chiral molecules have chiral centres.
Redox reactions play a pivotal role in chemistry and biology. The values of standard redox potential $$\left(\mathrm{E}^{\circ}\right)$$ of two half-cell reactions decide which way the reaction is expected to proceed. A simple example is a Daniel cell in which zinc goes into solution and copper gets deposited. Given below are a set of half-cell reactions (acidic medium) along with their $$\mathrm{E}^{\circ}$$ (V with respect to normal hydrogen electrode) values. Using this data obtain the correct explanations.
$$\begin{array}{ll} \mathrm{I}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{I}^{-} & \mathrm{E}^{\mathrm{o}}=0.54 \\ \mathrm{Cl}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cl}^{-} & \mathrm{E}^{\mathrm{o}}=1.36 \\ \mathrm{Mn}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+} & \mathrm{E}^{\mathrm{o}}=1.50 \\ \mathrm{Fe}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Fe}^{2+} & \mathrm{E}^{\mathrm{o}}=0.77 \\ \mathrm{O}_{2}+4 \mathrm{H}^{+}+4 \mathrm{e}^{-} \rightarrow 2 \mathrm{H}_{2} \mathrm{O} & \mathrm{E}^{\mathrm{o}}=1.23 \end{array}$$
Among the following, identify the correct statement.
JEE Advanced Papers
All year-wise previous year question papers