1
IIT-JEE 2007 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1
This question contains STATEMENT-1 (Assertion) and STATEMENT-2 (Reason) and has 4 choices (a), (b), (c), (d) out of which ONLY ONE is correct.

STATEMENT-1 : Band gap in germanium is small. because

STATEMENT-2 : The energy gap of each germanium atomic energy level is infinitesimally small.
A
Statement - 1 is True, Statement - 2 is True; Statement - 2 is a correct explanation for Statement - 1
B
Statement - 1 is True, Statement - 2 is True; Statement - 2 is not a correct explanation for Statement - 1
C
Statement - 1 is True, Statement - 2 is False
D
Statement - 1 is False, Statement - 2 is True
2
IIT-JEE 2007 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1
Consider a reaction aG + bH $$\to$$ Products. When concentration of both the reactants G and H is doubled, the rate increases by eight times. However, when concentration of G is doubled keeping the concentration of H fixed, the rate is doubled. The overall order of the reaction is
A
0
B
1
C
2
D
3
3
IIT-JEE 2007 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1
Let $${E^c}$$ denote the complement of an event $$E.$$ Let $$E, F, G$$ be pairwise independent events with $$P\left( G \right) > 0$$ and $$P\left( {E \cap F \cap G} \right) = 0.$$ Then $$P\left( {{E^c} \cap {F^c}|G} \right)$$ equals
A
$$P\left( {{E^c}} \right) + P\left( {{F^c}} \right)$$
B
$$P\left( {{E^c}} \right) - P\left( {{F^c}} \right)$$
C
$$P\left( {{E^c}} \right) - P\left( F \right)$$
D
$$P\left( E \right) - P\left( {{F^c}} \right)$$
4
IIT-JEE 2007 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

A student performs an experiment to determine the Young's modulus of a wire, exactly 2 m long, by Searle's method. In a particular reading, the student measures the extension in the length of the wire to be 0.8 mm with an uncertainty of $$\pm0.05\;\mathrm{mm}$$ at a load of exactly 1.0 kg. The student also measures the diameter of the wire to be 0.4 mm with an uncertainty of $$\pm0.01\;\mathrm{mm}$$. Take g = 9.8 m/s2 (exact). The Young's modulus obtained from the reading is

A
$$\left(2.0\;\pm\;0.3\right)\times10^{11}\;\mathrm N/\mathrm m^2$$
B
$$\left(2.0\;\pm\;0.2\right)\times10^{11}\;\mathrm N/\mathrm m^2$$
C
$$\left(2.0\;\pm\;0.1\right)\times10^{11}\;\mathrm N/\mathrm m^2$$
D
$$\left(2.0\;\pm\;0.05\right)\times10^{11}\;\mathrm N/\mathrm m^2$$
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