1
IIT-JEE 2002 Screening
MCQ (Single Correct Answer)
+3
-0.75
Let $$P = \left( { - 1,\,0} \right),\,Q = \left( {0,\,0} \right)$$ and $$R = \left( {3,\,3\sqrt 3 } \right)$$ be three points.
Then the equation of the bisector of the angle $$PQR$$ is
A
$${{\sqrt 3 } \over 2}x + y = 0$$
B
$$x + \sqrt 3 y = 0$$
C
$$\sqrt 3 x + y = 0$$
D
$$x + {{\sqrt 3 } \over 2}y = 0$$
2
IIT-JEE 2002 Screening
MCQ (Single Correct Answer)
+3
-0.75
A straight line through the origin $$O$$ meets the parallel lines $$4x+2y=9$$ and $$2x+y+6=0$$ at points $$P$$ and $$Q$$ respectively. Then the point $$O$$ divides the segemnt $$PQ$$ in the ratio
A
$$1 : 2$$
B
$$3 : 4$$
C
$$2 : 1$$
D
$$4 : 3$$
3
IIT-JEE 2002 Screening
MCQ (Single Correct Answer)
+2
-0.5
If the tangent at the point P on the circle $${x^2} + {y^2} + 6x + 6y = 2$$ meets a straight line 5x - 2y + 6 = 0 at a point Q on the y-axis, then the lenght of PQ is
A
4
B
$${2\sqrt 5 }$$
C
5
D
$${3\sqrt 5 }$$
4
IIT-JEE 2002 Screening
MCQ (Single Correct Answer)
+2
-0.5
If $$a > 2b > 0$$ then the positive value of $$m$$ for which $$y = mx - b\sqrt {1 + {m^2}} $$ is a common tangent to $${x^2} + {y^2} = {b^2}$$ and $${\left( {x - a} \right)^2} + {y^2} = {b^2}$$ is
A
$${{2b} \over {\sqrt {{a^2} - 4{b^2}} }}$$
B
$${{\sqrt {{a^2} - 4{b^2}} } \over {2b}}$$
C
$${{2b} \over {a - 2b}}$$
D
$${{b} \over {a - 2b}}$$
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