1
IIT-JEE 2002 Screening
MCQ (Single Correct Answer)
+4
-1
If $${\overrightarrow a }$$ and $${\overrightarrow b }$$ are two unit vectors such that $${\overrightarrow a + 2\overrightarrow b }$$ and $${5\overrightarrow a - 4\overrightarrow b }$$ are perpendicular to each other then the angle between $$\overrightarrow a $$ and $$\overrightarrow b $$ is
A
$${45^ \circ }$$
B
$${60^ \circ }$$
C
$${\cos ^{ - 1}}\left( {{1 \over 3}} \right)$$
D
$${\cos ^{ - 1}}\left( {{2 \over 7}} \right)$$
2
IIT-JEE 2002 Screening
MCQ (Single Correct Answer)
+4
-1
Let $$\overrightarrow V = 2\overrightarrow i + \overrightarrow j - \overrightarrow k $$ and $$\overrightarrow W = \overrightarrow i + 3\overrightarrow k .$$ If $$\overrightarrow U $$ is a unit vector, then the maximum value of the scalar triple product $$\left| {\overrightarrow U \overrightarrow V \overrightarrow W } \right|$$ is
A
$$-1$$
B
$$\sqrt {10} + \sqrt 6 $$
C
$$\sqrt {59} $$
D
$$\sqrt {60} $$
3
IIT-JEE 2002 Screening
MCQ (Single Correct Answer)
+3
-0.75
The integral $$\int\limits_{ - 1/2}^{1/2} {\left( {\left[ x \right] + \ell n\left( {{{1 + x} \over {1 - x}}} \right)} \right)dx} $$ equal to
A
$$ - {1 \over 2}$$
B
$$0$$
C
$$1$$
D
$$2\ell n\left( {{1 \over 2}} \right)$$
4
IIT-JEE 2002 Screening
MCQ (Single Correct Answer)
+3
-0.75
The area bounded by the curves $$y = \left| x \right| - 1$$ and $$y = - \left| x \right| + 1$$ is
A
$$1$$
B
$$2$$
C
$$2\sqrt 2 $$
D
$$4$$

JEE Advanced Papers

All year-wise previous year question papers