1
IIT-JEE 2002 Screening
MCQ (Single Correct Answer)
+2
-0.5
The point(s) in the curve $${y^3} + 3{x^2} = 12y$$ where the tangent is vertical, is (are)
A
$$\left( { \pm {4 \over {\sqrt 3 }}, - 2} \right)$$
B
$$\left( { \pm \sqrt {{{11} \over 3}} ,1} \right)$$
C
$$(0,0)$$
D
$$\left( { \pm {4 \over {\sqrt 3 }}, 2} \right)$$
2
IIT-JEE 2002 Screening
MCQ (Single Correct Answer)
+4
-1
If $${\overrightarrow a }$$ and $${\overrightarrow b }$$ are two unit vectors such that $${\overrightarrow a + 2\overrightarrow b }$$ and $${5\overrightarrow a - 4\overrightarrow b }$$ are perpendicular to each other then the angle between $$\overrightarrow a $$ and $$\overrightarrow b $$ is
A
$${45^ \circ }$$
B
$${60^ \circ }$$
C
$${\cos ^{ - 1}}\left( {{1 \over 3}} \right)$$
D
$${\cos ^{ - 1}}\left( {{2 \over 7}} \right)$$
3
IIT-JEE 2002 Screening
MCQ (Single Correct Answer)
+4
-1
Let $$\overrightarrow V = 2\overrightarrow i + \overrightarrow j - \overrightarrow k $$ and $$\overrightarrow W = \overrightarrow i + 3\overrightarrow k .$$ If $$\overrightarrow U $$ is a unit vector, then the maximum value of the scalar triple product $$\left| {\overrightarrow U \overrightarrow V \overrightarrow W } \right|$$ is
A
$$-1$$
B
$$\sqrt {10} + \sqrt 6 $$
C
$$\sqrt {59} $$
D
$$\sqrt {60} $$
4
IIT-JEE 2002 Screening
MCQ (Single Correct Answer)
+3
-0.75
The integral $$\int\limits_{ - 1/2}^{1/2} {\left( {\left[ x \right] + \ell n\left( {{{1 + x} \over {1 - x}}} \right)} \right)dx} $$ equal to
A
$$ - {1 \over 2}$$
B
$$0$$
C
$$1$$
D
$$2\ell n\left( {{1 \over 2}} \right)$$

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