GATE ECE 2003 | GATE ECE Year Wise Previous Years Questions

GATE ECE 2003

MCQ (Single Correct Answer)

-0.6

A sinusoidal signal with peak-to-peak amplitude of 1.536V is quantized into 128 levels using a mid-rise uniform quantizer. The quantization-noise power is

$$0.768$$

$$48 \times {10^{ - 6}}{V^2}$$

$$12 \times {10^{ - 6}}{V^2}$$

$$3.072 V$$

GATE ECE 2003

MCQ (Single Correct Answer)

-0.6

Let x(t) be the input to a linear, time-invariant system. The required output is 4x(t-2). The transfer function of the system should be

4 e^{$$j4\pi f$$}

2 e^{$$-j8\pi f$$}

4 e^{$$-j4\pi f$$}

2 e^{$$j8\pi f$$}

GATE ECE 2003

MCQ (Single Correct Answer)

-0.6

The signal flow graph of a system is shown in figure. The transfer function $$\frac{C(s)}{R(s)}$$ of the system is GATE ECE 2003 Control Systems - Signal Flow Graph and Block Diagram Question 15 English

GATE ECE 2003 Control Systems - Signal Flow Graph and Block Diagram Question 15 English

$$\frac{6}{s^2+29s+6}$$

$$\frac{6s}{s^2+29s+6}$$

$$\frac{s(s+2)}{s^2+29s+6}$$

$$\frac{s(s+27)}{s^2+29s+6}$$

GATE ECE 2003

MCQ (Single Correct Answer)

-0.6

A second-order system has the transfer function $$\frac{C\left(s\right)}{R\left(s\right)}=\frac4{s^2+4s+4}$$. With r(t) as the unit-step function, the response c(t) of the system is represented by

GATE ECE 2003 Control Systems - Time Response Analysis Question 16 English Option 1

GATE ECE 2003 Control Systems - Time Response Analysis Question 16 English Option 2

GATE ECE 2003 Control Systems - Time Response Analysis Question 16 English Option 3

GATE ECE 2003 Control Systems - Time Response Analysis Question 16 English Option 4

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