MHT CET 2026 11th April Evening Shift | Rotational Motion Question 31 | Physics

The moment of inertia of a ring about an axis passing through its centre and perpendicular to its plane is I. It is rotating with angular velocity $\omega$. Another identical ring is gently placed on it so that their centres coincide. If both rings are rotating about the same axis then loss in kinetic energy is

$I\omega^2$

$\dfrac{I\omega^2}{2}$

$\dfrac{I\omega^2}{4}$

$\dfrac{I\omega^2}{8}$

MHT CET 2026 11th April Evening Shift

MCQ (Single Correct Answer)

-0

Let M and L be the mass and length of thin uniform rod respectively. In first case, axis of rotation is passing through centre and perpendicular to length of rod. In second case axis of rotation is passing through one end and perpendicular to length of rod. The ratio of radius of gyration in first case to second case is

$\dfrac{1}{4}$

$\dfrac{1}{2}$

$\dfrac{1}{8}$

$\dfrac{1}{6}$

MHT CET 2026 11th April Morning Shift

MCQ (Single Correct Answer)

-0

A wheel is rotating at $600$ rpm about its axis of rotation. When the power is cut off, it comes to rest in half a minute. Its angular retardation expressed in $\text{rad}/\text{s}^2$ is (retardation is uniform)

$\dfrac{2\pi}{3}$

$\dfrac{\pi}{4}$

$\pi$

$\dfrac{\pi}{6}$

MHT CET 2026 11th April Morning Shift

MCQ (Single Correct Answer)

-0

A flywheel rotating about a fixed axis has a kinetic energy of $500$ joule, if its angular frequency is $5$ Hz, then calculate the moment of inertia of the wheel about the axis of rotation. ($\pi^2=10$)

$0.6 \text{ kg m}^2$

$1 \text{ kg m}^2$

$0.75 \text{ kg m}^2$

$0.15 \text{ kg m}^2$

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