1
MHT CET 2024 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The moment of inertia of uniform circular disc is maximum about an axis perpendicular to the disc and passing through point

MHT CET 2024 10th May Morning Shift Physics - Rotational Motion Question 12 English

A
A
B
B
C
C
D
D
2
MHT CET 2024 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A ring and a disc roll on horizontal surface without slipping with same linear velocity. If both have same mass and total kinetic energy of the ring is 6 J then total kinetic energy of the disc is

A
$\frac{3}{2} \mathrm{~J}$
B
$\frac{5}{2} \mathrm{~J}$
C
$\frac{7}{2} \mathrm{~J}$
D
$\frac{9}{2} \mathrm{~J}$
3
MHT CET 2024 10th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A solid metallic sphere of radius ' $R$ ' having moment of inertia '$I$' about diameter is melted and recast into a solid disc of radius ' $r$ ' of a uniform thickness. The moment of inertia of a disc about an axis passing through its edge and perpendicular to its plane is also equal to '$I$'. The ratio $\frac{r}{R}$ is

A
$\frac{1}{\sqrt{2}}$
B
$\frac{2}{\sqrt{5}}$
C
$\frac{2}{\sqrt{10}}$
D
$\frac{2}{\sqrt{15}}$
4
MHT CET 2024 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A particle of mass ' m ' is rotating in a circular path of radius ' $r$ '. Its angular momentum is ' $L$ ' The centripetal force acting on it is ' $F$ '. The relation between ' $F$ ', ' $L$ ', ' $r$ ' and ' $m$ ' is

A
$\mathrm{F}=\frac{\mathrm{L}}{\mathrm{mr}^2}$
B
$\mathrm{L}=\mathrm{m}^2 \mathrm{Fr}^2$
C
$\frac{\mathrm{L}^2}{\mathrm{~m}}=\mathrm{Fr}^3$
D
$\frac{\mathrm{F}}{\mathrm{L}^3}=\mathrm{mr}^2$
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