MHT CET 2026 19th April Morning Shift | Rotational Motion Question 6 | Physics

A thin uniform rod AB of mass '$m$' and length '$l$' is hinged at one end A to the ground level. Initially the rod stands vertically and is allowed to fall freely to the ground in the vertical plane. The angular velocity of the rod when its B end strikes the ground is
($g$ = acceleration due to gravity)

$\sqrt{\dfrac{2g}{l}}$

$\sqrt{\dfrac{3g}{l}}$

$\sqrt{\dfrac{mg}{l}}$

$\sqrt{\dfrac{mg}{3l}}$

MHT CET 2026 19th April Morning Shift

MCQ (Single Correct Answer)

-0

The radius of gyration of a solid sphere of radius 'R' and mass 'M' about its diameter is $K_d$ and that about a tangent of a solid sphere is $K_t$. The ratio of $K_d$ to $K_t$ is

$\left(\dfrac{7}{5}\right)^{1/2}$

$\left(\dfrac{7}{2}\right)^{1/2}$

$\left(\dfrac{2}{7}\right)^{1/2}$

$\left(\dfrac{2}{5}\right)^{1/2}$

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

The angular momentum of a rotating body is ' $L$ '. When the frequency of rotating body is tripled and its kinetic energy is made one-third, the new angular momentum becomes

$\frac{1}{9} \mathrm{~L}$

$\frac{1}{3} \mathrm{~L}$

6 L

9 L

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

The moment of inertia of a thin uniform rod of mass ' $M$ ' and length ' $L$ ', about an axis perpendicular to length of the rod and at a distance ' $L / 4$ ' from one end is

$\frac{\mathrm{ML}^2}{6}$

$\frac{\mathrm{ML}^2}{12}$

$\frac{7 \mathrm{ML}^2}{24}$

$\frac{7 \mathrm{ML}^2}{48}$

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