MHT CET 2024 15th May Evening Shift | Rotational Motion Question 4 | Physics

A body of mass $m$ slides down an incline and reaches the bottom with a velocity V . If the same mass were in the form of a disc which rolls down this incline, the velocity of the disc at bottom would have been

$\mathrm{v} \sqrt{\frac{3}{4}}$

$\mathrm{v} \sqrt{\frac{3}{2}}$

$v \sqrt{\frac{1}{3}}$

$\mathrm{v} \sqrt{\frac{2}{3}}$

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

The radius of gyration of a circular disc of radius R and mass m rotating about diameter as axis is

$\mathrm{R} \sqrt{2}$

$\mathrm{R} / \sqrt{2}$

$\mathrm{R} / 2$

$\mathrm{R}$

MHT CET 2024 15th May Morning Shift

MCQ (Single Correct Answer)

-0

A thin uniform metal rod of mass ' $M$ ' and length ' $L$ ' is swinging about a horizontal axis passing through its end. Its maximum angular velocity is ' $\omega$ '. Its centre of mass rises to a maximum height of ( $\mathrm{g}=$ Acceleration due to gravity)

$\frac{\mathrm{L}^2 \omega^2}{3 \mathrm{~g}}$

$\frac{\mathrm{L}^2 \omega^2}{2 \mathrm{~g}}$

$\frac{\mathrm{L}^2 \omega^2}{6 \mathrm{~g}}$

$\frac{\mathrm{L}^2 \omega^2}{4 \mathrm{~g}}$

MHT CET 2024 15th May Morning Shift

MCQ (Single Correct Answer)

-0

Three thin rods, each of mass ' $M$ ' and length ' $L$ ' are placed along $\mathrm{X}, \mathrm{Y}$ and Z axes which are mutually perpendicular. One end of each rod is at origin. M. I. of the system about Z axis is

$\frac{3 \mathrm{ML}^2}{4}$

$\frac{2 M^2}{5}$

$\frac{2 \mathrm{ML}^2}{3}$

$\frac{3 \mathrm{ML}^2}{5}$

PREVIOUS NEXT

MHT CET Subjects