MHT CET 2021 23rd September Evening Shift | Rotational Motion Question 66 | Physics

The moment of inertia of a body about the given axis, rotating with angular velocity 1 rad/s is numerically equal to 'P' times its rotational kinetic energy. The value of 'P' is

$$\frac{1}{4}$$

$$\frac{1}{2}$$

MHT CET 2021 23rd September Evening Shift

MCQ (Single Correct Answer)

-0

Two circular loops P and Q are made from a uniform wire. The radii of P and Q are R$$_1$$ and R$$_2$$ respectively. The momentsw of inertia about their own axis are $$\mathrm{I_P}$$ and $$\mathrm{I_Q}$$ respectively. If $$ \frac{\mathrm{I}_{\mathrm{P}}}{\mathrm{I}_Q}=\frac{1}{8}$$ then $$\mathrm{\frac{R_2}{R_1}}$$ is

MHT CET 2021 23rd September Evening Shift

MCQ (Single Correct Answer)

-0

A metre scale is supported on a wedge at its centre of gravity. A body of weight 'w'. is suspended from the $$20 \mathrm{~cm}$$ mark and another weight of 25 gram is suspended from $$74 \mathrm{~cm}$$ mark balance it and the metre scale remains perfectly horizontal. Neglecting the weight of the metre scale, the weight of the body is

20 gram-wt

15 gram-wt

33 gram-wt

30 gram-wt

MHT CET 2021 23rd September Evening Shift

MCQ (Single Correct Answer)

-0

A body of mass 'm' and radius of gyration 'K' has an angular momentum 'L'. Then its angular velocity is

$$\frac{\mathrm{L}}{\mathrm{mK}^2}$$

$$\frac{\mathrm{mK}^2}{\mathrm{~L}}$$

$$\frac{\mathrm{K}^2}{\mathrm{~mL}}$$

$$\mathrm{mK}^2 \mathrm{~L}$$

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