MHT CET 2021 24th September Morning Shift | Rotational Motion Question 30 | Physics

Two identical particles each of mass '$$m$$' are separated by a distance '$$d$$'. The axis of rotation passes through the midpoint of '$$\mathrm{d}$$' and is perpendicular to the length $$\mathrm{d}$$. If '$$\mathrm{K}$$' is the average rotational kinetic energy of the system, then the angular frequency is

$$2 \mathrm{~d} \sqrt{\frac{\mathrm{m}}{\mathrm{K}}}$$

$$\frac{\mathrm{d}}{2} \sqrt{\frac{\mathrm{K}}{\mathrm{m}}}$$

$$\frac{2}{\mathrm{~d}} \sqrt{\frac{\mathrm{K}}{\mathrm{m}}}$$

$$\frac{d}{4} \sqrt{\frac{\mathrm{m}}{\mathrm{K}}}$$

MHT CET 2021 24th September Morning Shift

MCQ (Single Correct Answer)

-0

A body of mass '$$\mathrm{m}$$' and radius of gyration '$$\mathrm{K}$$' has an angular momentum $$\mathrm{L}$$. Its angular velocity is

$$\frac{\mathrm{K}^2}{\mathrm{~mL}}$$

$$\mathrm{mK}^2 \mathrm{~L}$$

$$\frac{\mathrm{mK}^2}{\mathrm{~L}}$$

$$\frac{\mathrm{L}}{\mathrm{mK}^2}$$

MHT CET 2021 23rd September Evening Shift

MCQ (Single Correct Answer)

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The moment of inertia of a body about the given axis, rotating with angular velocity 1 rad/s is numerically equal to 'P' times its rotational kinetic energy. The value of 'P' is

$$\frac{1}{4}$$

$$\frac{1}{2}$$

MHT CET 2021 23rd September Evening Shift

MCQ (Single Correct Answer)

-0

Two circular loops P and Q are made from a uniform wire. The radii of P and Q are R$$_1$$ and R$$_2$$ respectively. The momentsw of inertia about their own axis are $$\mathrm{I_P}$$ and $$\mathrm{I_Q}$$ respectively. If $$ \frac{\mathrm{I}_{\mathrm{P}}}{\mathrm{I}_Q}=\frac{1}{8}$$ then $$\mathrm{\frac{R_2}{R_1}}$$ is

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