MHT CET 2021 21th September Evening Shift | Wave Optics Question 55 | Physics

Two coherent sources of wavelength '$$\lambda$$' produce steady interference pattern. The path difference corresponding to 10$$^{th}$$ order maximum will be

9.5 $$\lambda$$

10.5 $$\lambda$$

9 $$\lambda$$

10 $$\lambda$$

MHT CET 2021 21th September Evening Shift

MCQ (Single Correct Answer)

-0

In Young's experiment, fringes are obtained on a screen placed at a distance $$75 \mathrm{~cm}$$ from the slits. When the separation between two narrow slits is doubled, then the fringe width is decreased. In order to obtain the initial fringe width, the screen should be moved through.

$$150 \mathrm{~cm}$$ away from the slits.

$$75 \mathrm{~cm}$$ towards the slits.

$$75 \mathrm{~cm}$$ away from slits.

$$150 \mathrm{~cm}$$ towards the slits.

MHT CET 2021 21th September Evening Shift

MCQ (Single Correct Answer)

-0

Two coherent sources 'P' and 'Q' produce interference at point 'A' on the screen, where there is a dark band which is formed between 4^th and 5^th bright band. Wavelength of light used is 6000 $$\mathop A\limits^o $$. The path difference PA and QA is

$$\mathrm{3.6\times10^{-4}~cm}$$

$$\mathrm{3.2\times10^{-4}~cm}$$

$$\mathrm{2.4\times10^{-4}~cm}$$

$$\mathrm{2.7\times10^{-4}~cm}$$

MHT CET 2021 21th September Morning Shift

MCQ (Single Correct Answer)

-0

In diffraction experiment, from a single slit, the angular width of central maximum does NOT depend upon

ratio of wavelength and slit width

distance of the slit from the screen

wavelength of light used

width of the slit

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