1
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment, in an interference pattern, a minimum is observed exactly in front of one slit. The distance between the two coherent sources is '$$\mathrm{d}$$' and '$$\mathrm{D}$$' is the distance between the source and screen. The possible wavelengths used are inversely proportional to

A
D, 5D, 9D, ....
B
$$\mathrm{D}, 3 \mathrm{D}, 5 \mathrm{D}, \ldots$$
C
$$3 \mathrm{D}, 4 \mathrm{D}, 5 \mathrm{D}, \ldots$$
D
$$3 \mathrm{D}, 7 \mathrm{D}, 10 \mathrm{D}, \ldots$$
2
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A beam of light having wavelength $$5400 \mathrm{~A}$$ from a distant source falls on a single slit $$0.96 \mathrm{~mm}$$ wide and the resultant diffraction pattern is observed on a screen $$2 \mathrm{~m}$$ away. What is the distance between the first dark fringe on either side of central bright fringe?

A
4.8 mm
B
1.2 mm
C
2.4 mm
D
3.6 mm
3
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two beams of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the beams is $$\pi / 2$$ at point $$\mathrm{A}$$ and $$\pi$$ at point $$\mathrm{B}$$. Then the difference between the resultant intensities at $$\mathrm{A}$$ and $$\mathrm{B}$$ is

A
4I
B
5I
C
2I
D
3I
4
MHT CET 2021 23rd September Evening Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment, the intensity at a point where path difference is $$\frac{\lambda}{6}$$ ($$\lambda$$ being the wavelength of light used) is $$I^{\prime}$$. If '$$I_0$$' denotes the maximum intensity, then $$\frac{I}{I_0}$$ is equal to $$\left(\cos 0^{\circ}=1, \cos 60^{\circ}=\frac{1}{\lambda}\right)$$

A
$$\frac{\sqrt{3}}{2}$$
B
$$\frac{4}{3}$$
C
$$\frac{1}{\sqrt{2}}$$
D
$$\frac{1}{2}$$
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