1
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The diffraction fringes obtained by a single slit are of

A
equal width
B
equal width and unequal intensity
C
unequal width but equal intensity
D
unequal width and unequal intensity
2
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In Young's double slit experiment, $$8^{\text {th }}$$ maximum with wavelength '$$\lambda_1$$' is at a distance '$$d_1$$' from the central maximum and $$6^{\text {th }}$$ maximum with wavelength '$$\lambda_2$$' is at a distance '$$\mathrm{d}_2$$'. Then $$\frac{\mathrm{d}_2}{\mathrm{~d}_1}$$ is

A
$$\frac{3 \lambda_1}{4 \lambda_2}$$
B
$$\frac{3 \lambda_2}{4 \lambda_1}$$
C
$$\frac{4 \lambda_1}{3 \lambda_2}$$
D
$$\frac{4 \lambda_2}{3 \lambda_1}$$
3
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $$\mathrm{I}_0$$ is the intensity of the principal maximum in the single slit diffraction pattern, then what will be the intensity when the slit width is doubled?

A
$$\frac{\mathrm{I}_0}{2}$$
B
$$\mathrm{I}_0$$
C
$$4 \mathrm{I}_0$$
D
$$2 \mathrm{I}_0$$
4
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Light of wavelength $$5000 \mathop A\limits^o$$ is incident normally on a slit. The first minimum of the diffraction pattern is observed to lie at a distance of $$5 \mathrm{~mm}$$ from the central maximum on a screen placed at a distance of $$2 \mathrm{~m}$$ from the slit. The width of the slit is

A
2 cm
B
0.2 cm
C
0.02 cm
D
0.01 cm
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