1
MHT CET 2023 9th May Evening Shift
+1
-0

Light of wavelength ',$$\lambda$$' is incident on a slit of width '$$\mathrm{d}$$'. The resulting diffraction pattern is observed on a screen at a distance '$$D$$'. The linear width of the principal maximum is then equal to the width of the slit if $$D$$ equals

A
$$\frac{d}{\lambda}$$
B
$$\frac{\mathrm{d}^2}{2 \lambda}$$
C
$$\frac{2 \lambda}{\mathrm{d}}$$
D
$$\frac{2 \lambda^2}{d}$$
2
MHT CET 2023 9th May Evening Shift
+1
-0

In Young's double slit experiment, the wavelength of light used is '$$\lambda$$'. The intensity at a point is '$$\mathrm{I}$$' where path difference is $$\left(\frac{\lambda}{4}\right)$$. If $$I_0$$ denotes the maximum intensity, then the ratio $$\left(\frac{\mathrm{I}}{\mathrm{I}_0}\right)$$ is

$$\left(\sin \frac{\pi}{4}=\cos \frac{\pi}{4}=\frac{1}{\sqrt{2}}\right)$$

A
$$\frac{1}{\sqrt{2}}$$
B
$$\frac{1}{2}$$
C
$$\frac{3}{4}$$
D
$$\frac{\sqrt{3}}{2}$$
3
MHT CET 2023 9th May Evening Shift
+1
-0

In Young's double slit experiment, the fringe width is $$2 \mathrm{~mm}$$. The separation between the $$13^{\text {th }}$$ bright fringe and the $$4^{\text {th }}$$ dark fringe from the centre of the screen on same side will be

A
$$13 \mathrm{~mm}$$.
B
$$17 \mathrm{~mm}$$.
C
$$19 \mathrm{~mm}$$.
D
$$23 \mathrm{~mm}$$.
4
MHT CET 2023 9th May Morning Shift
+1
-0

A beam of unpolarized light passes through a tourmaline crystal A and then it passes through a second tourmaline crystal B oriented so that its principal plane is parallel to that of A. The intensity of emergent light is $$I_0$$. Now B is rotated by $$45^{\circ}$$ about the ray. The emergent light will have intensity $$\left(\cos 45^{\circ}=\frac{1}{\sqrt{2}}\right)$$

A
$$\frac{\mathrm{I}_0}{2}$$
B
$$\frac{\mathrm{I}_0}{\sqrt{2}}$$
C
$$\frac{\sqrt{2}}{\mathrm{I}_0}$$
D
$$\frac{2}{\mathrm{I}_0}$$
MHT CET Subjects
Physics
Mechanics
Optics
Electromagnetism
Modern Physics
Chemistry
Physical Chemistry
Inorganic Chemistry
Organic Chemistry
Mathematics
Algebra
Trigonometry
Calculus
Coordinate Geometry
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