MHT CET 2023 11th May Morning Shift | Wave Optics Question 21 | Physics

A double slit experiment is immersed in water of refractive index 1.33. The slit separation is $$1 \mathrm{~mm}$$, distance between slit and screen is $$1.33 \mathrm{~m}$$ The slits are illuminated by a light of wavelength $$6300 \mathop A\limits^o$$. The fringe width is

$$4.9 \times 10^{-4} \mathrm{~m}$$

$$5.8 \times 10^{-4} \mathrm{~m}$$

$$6.3 \times 10^{-4} \mathrm{~m}$$

$$8.6 \times 10^{-4} \mathrm{~m}$$

MHT CET 2023 11th May Morning Shift

MCQ (Single Correct Answer)

-0

In the experiment of diffraction due to a single slit, if the slit width is decreased, the width of the central maximum

becomes zero.

does not change.

increases.

decreases.

MHT CET 2023 11th May Morning Shift

MCQ (Single Correct Answer)

-0

In biprism experiment, if $$5^{\text {th }}$$ bright band with wavelength $$\lambda_1^{\prime}$$ coincides with $$6^{\text {th }}$$ dark band with wavelength $$\lambda_2{ }^{\prime}$$ then the ratio $$\left(\frac{\lambda_2}{\lambda_1}\right)$$ is

$$\frac{9}{7}$$

$$\frac{7}{9}$$

$$\frac{10}{11}$$

$$\frac{11}{10}$$

MHT CET 2023 10th May Evening Shift

MCQ (Single Correct Answer)

-0

In Young's double slit experiment, the two slits are 'd' distance apart. Interference pattern is observed on a screen at a distance 'D' from the slits. A dark fringe is observed on a screen directly opposite to one of the slits. The wavelength of light is

$$\frac{\mathrm{D}^2}{2 \mathrm{~d}}$$

$$\frac{\mathrm{d}^2}{2 \mathrm{D}}$$

$$\frac{\mathrm{D}^2}{\mathrm{~d}}$$

$$\frac{d^2}{D}$$

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