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MHT CET 2019 2nd May Morning Shift
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The real force ' $F$ ' acting on a particle of mass $m$ ' performing circular motion acts along the radius of circle ' $r$ ' and is directed towards the centre of circle. The square root of magnitude of such force is ( $T=$ periodic time)

A
$\frac{2 \pi}{T} \sqrt{m r}$
B
$\frac{T m r}{4 \pi}$
C
$\frac{2 \pi T}{\sqrt{m r}}$
D
$\frac{T^2 m r}{4 \pi}$
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