1
MHT CET 2024 11th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The plane $2 x+3 y+4 z=1$ meets $X$-axis in $A$, Y -axis in B and Z -axis in C . Then the centroid of $\triangle A B C$ is

A
$(2,3,4)$
B
$\left(\frac{1}{2}, \frac{1}{3}, \frac{1}{4}\right)$
C
$\left(\frac{1}{6}, \frac{1}{9}, \frac{1}{12}\right)$
D
$\left(\frac{3}{2}, \frac{3}{3}, \frac{3}{4}\right)$
2
MHT CET 2024 11th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If the lines $\frac{x+1}{-10}=\frac{y+k}{-1}=\frac{z-4}{1} \quad$ and $\frac{x+10}{-1}=\frac{y+1}{-3}=\frac{z-1}{4}$ intersect each other, then the value of $k$ is

A
$-$3
B
3
C
4
D
2
3
MHT CET 2024 11th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The equation of the line passing through the point $(3,1,2)$ and perpendicular to the lines $\frac{x-1}{1}=\frac{y-2}{2}=\frac{z-3}{3}$ and $\frac{x}{-3}=\frac{y}{2}=\frac{z}{5}$ is

A
$\frac{x+3}{2}=\frac{y+1}{7}=\frac{z+2}{4}$
B
$\frac{x-3}{-2}=\frac{y-1}{7}=\frac{z-2}{4}$
C
$\frac{x-3}{2}=\frac{y-1}{-7}=\frac{z-2}{4}$
D
$\frac{x-3}{2}=\frac{y-1}{5}=\frac{z-2}{4}$
4
MHT CET 2024 11th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The area of the triangle with vertices $(1,2,0)$, $(1,0,2)$ and $(0,3,1)$ is

A
$\sqrt{3}$ sq. units
B
$\sqrt{6}$ sq. units
C
$\sqrt{5}$ sq. units
D
$\sqrt{7}$ sq. units
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