1
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The centroid of tetrahedron with vertices at $$\mathrm{A}(-1,2,3), \mathrm{B}(3,-2,1), \mathrm{C}(2,1,3)$$ and $$\mathrm{D}(-1,-2,4)$$ is

A
$$\left(\frac{3}{4}, \frac{-1}{4}, \frac{11}{4}\right)$$
B
$$\left(\frac{5}{4}, \frac{-3}{4}, \frac{7}{4}\right)$$
C
$$\left(\frac{-3}{4}, \frac{-1}{4}, \frac{11}{4}\right)$$
D
$$\left(\frac{-5}{4}, \frac{-3}{4}, \frac{-7}{4}\right)$$
2
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

A plane is parallel to two lines whose direction ratios are $$1,0,-1$$ and $$-1,1,0$$ and it contains the point $$(1,1,1)$$. If it cuts the co-ordinate axes at $$\mathrm{A}, \mathrm{B}, \mathrm{C}$$, then the volume of the tetrahedron $$\mathrm{OABC}$$ (in cubic units) is

A
$$\frac{9}{4}$$
B
$$\frac{9}{2}$$
C
9
D
27
3
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The equation of the plane through $$(-1,1,2)$$ whose normal makes equal acute angles with co-ordinate axes is

A
$$x+y+z-3=0$$
B
$$x+y+z-2=0$$
C
$$x+y-z-2=0$$
D
$$x-y+z-3=0$$
4
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The distance of the point $$\mathrm{P}(-2,4,-5)$$ from the line $$\frac{x+3}{3}=\frac{y-4}{5}=\frac{z+8}{6}$$ is

A
$$\frac{\sqrt{37}}{10}$$
B
$$\sqrt{\frac{37}{10}}$$
C
$$\frac{37}{\sqrt{10}}$$
D
$$\frac{37}{10}$$
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