1
MHT CET 2025 23rd April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The angle between the line $x=\frac{y-1}{2}=\frac{z-3}{\lambda}$ and the plane $x+2 y+3 z=6$ is $\cos ^{-1} \sqrt{\frac{5}{14}}$, then the value of $\lambda$ is

A
$\frac{2}{3}$
B
$\frac{4}{3}$
C
$\frac{1}{3}$
D
$\frac{5}{3}$
2
MHT CET 2025 23rd April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The equation of the line passing through the point of intersection of $\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}$ and $\frac{x-4}{5}=\frac{y-1}{2}=z$ and also through the point ( $2,1,-2$ ) is

A

$\overline{\mathrm{r}}=(-\hat{\mathrm{i}}-\hat{\mathrm{j}}-\hat{\mathrm{k}})+\lambda(\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\hat{\mathrm{k}})$

B

$\overline{\mathrm{r}}=(-\hat{\mathrm{i}}-\hat{\mathrm{j}}+\hat{\mathrm{k}})+\lambda(2 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\hat{\mathrm{k}})$

C

$\frac{x+1}{3}=\frac{y+1}{2}=\frac{z+1}{-1}$

D

$\frac{x-1}{3}=\frac{y-1}{2}=\frac{z+1}{1}$

3
MHT CET 2025 23rd April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If the lines $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}$ and $\frac{x-3}{1}=\frac{y-\mathrm{k}}{2}=\frac{\mathrm{z}}{1}$ intersect, then the value of k is

A
$\frac{3}{2}$
B
$-\frac{3}{2}$
C
$\frac{9}{2}$
D
$-\frac{2}{9}$
4
MHT CET 2025 23rd April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The distance of the point $\mathrm{P}(3,4,4)$ from the point of intersection of the line joining the points $\mathrm{Q}(3,-4,-5), \mathrm{R}(2,-3,1)$ and the plane $2 x+y+z=7$ is

A
7 units
B
9 units
C
11 units
D
6 units
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