MHT CET 2023 14th May Morning Shift | Circular Motion Question 17 | Physics

On dry road, the maximum speed of a vehicle along a circular path is '$$V$$'. When the road becomes wet, maximum speed becomes $$\frac{\mathrm{V}}{2}$$. If coefficient of friction of dry road is '$$\mu$$' then that of wet road is

$$\frac{2 \mu}{3}$$

$$\frac{\mu}{4}$$

$$\frac{\mu}{3}$$

$$\frac{3 \mu}{4}$$

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

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A string of length '$$L$$' fixed at one end carries a body of mass '$$\mathrm{m}$$' at the other end. The mass is revolved in a circle in the horizontal plane about a vertical axis passing through the fixed end of the string. The string makes angle '$$\theta$$' with the vertical. The angular frequency of the body is '$$\omega$$'. The tension in the string is

$$\mathrm{mL}^2 \omega$$

$$\mathrm{mL} \omega^2$$

$$\frac{\omega^2}{\mathrm{~mL}}$$

$$\frac{\mathrm{m} \omega^2}{\mathrm{~L}}$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

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A stone is projected at angle $$\theta$$ with velocity $$u$$. If it executes nearly a circular motion at its maximum point for short time, then the radius of the circular path will be ( $$g=$$ acceleration due to gravity)

$$\frac{u^2}{g}$$

$$\frac{u^2 \cos ^2 \theta}{g}$$

$$\frac{u^2 \sin ^2 \theta}{g}$$

$$\frac{u^2 \cos ^2 \theta}{2 g}$$

MHT CET 2023 12th May Evening Shift

MCQ (Single Correct Answer)

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A particle is moving in a circle with uniform speed '$$v$$'. In moving from a point to another diametrically opposite point

the momentum changes by $$\mathrm{mv}$$

the momentum changes by $$2 \mathrm{~mv}$$

the kinetic energy changes by $$\frac{1}{2} \mathrm{mv}^2$$

the kinetic energy changes by $$\mathrm{m v^2}$$

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