1
MHT CET 2025 21st April Evening Shift
MCQ (Single Correct Answer)
+2
-0

Let A be a non-singular matrix of order n and $|A|=k$, then $(\operatorname{adj} A)^{-1}$ is

A
$\frac{\mathrm{A}}{\mathrm{k}}$
B
$\quad \mathrm{k}^{\mathrm{n}-1}(\operatorname{adj} \mathrm{~A})$
C
$\mathrm{k}^{n-2} \mathrm{~A}$
D
kA
2
MHT CET 2025 21st April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The third element in the second row of adjoint of a matrix $A=\left[a_{i j}\right]_{3 \times 3}$ (where $a_{i j}=2 i+j$ ) is

A
2
B
-2
C
4
D
-4
3
MHT CET 2025 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $\left[\begin{array}{lll}1 & 3 & 3 \\ 1 & 4 & 4 \\ 1 & 3 & 4\end{array}\right]\left[\begin{array}{l}x \\ y \\ z\end{array}\right]=\left[\begin{array}{l}12 \\ 15 \\ 13\end{array}\right]$, then the value of $x^2+y^2+z^2=$

A
6
B
12
C
3
D
14
4
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $A=\left[\begin{array}{cc}1 & \tan x \\ -\tan x & 1\end{array}\right]$, then $A^T A^{-1}=$

A
$\left[\begin{array}{cc}\cos 2 x & -\sin 2 x \\ -\sin 2 x & \cos 2 x\end{array}\right]$
B
$\left[\begin{array}{ll}\cos 2 x & -\sin 2 x \\ \sin 2 x & \cos 2 x\end{array}\right]$
C
$\left[\begin{array}{cc}-\cos 2 x & \sin 2 x \\ \sin 2 x & \cos 2 x\end{array}\right]$
D
$\left[\begin{array}{ll}-\cos 2 x & \sin 2 x \\ -\sin 2 x & \cos 2 x\end{array}\right]$

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