1
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$A=\left[\begin{array}{cc}5 a & -b \\ 3 & 2\end{array}\right]$$ and $$A$$ adj $$A=A A^T$$, then $$5 a+b=$$

A
13
B
4
C
$$-$$1
D
5
2
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

For an invertible matrix $$A$$, if $$A(\operatorname{adj} A)=\left[\begin{array}{cc}20 & 0 \\ 0 & 20\end{array}\right]$$, then $$|A|=$$

A
$$-$$200
B
200
C
$$-$$2
D
20
3
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$A=\left[\begin{array}{ccc}1 & 2 & 1 \\ -1 & 1 & 3\end{array}\right]$$ and $$B=\left[\begin{array}{cc}1 & 2 \\ -3 & 1 \\ 0 & 2\end{array}\right]$$, then $$(A B)^{-1}$$

A
$$\left[\begin{array}{cc}5 & -6 \\ -4 & 5\end{array}\right]$$
B
$$\left[\begin{array}{ll}5 & 6 \\ 4 & 5\end{array}\right]$$
C
$$\left[\begin{array}{ll}-5 & 6 \\ -4 & 5\end{array}\right]$$
D
$$\left[\begin{array}{ll}-5 & -6 \\ -4 & -5\end{array}\right]$$
4
MHT CET 2021 21th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$A=\left[\begin{array}{ccc}\cos \theta & -\sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1\end{array}\right]$$, then $$\operatorname{adj} A=$$

A
$$\left[\begin{array}{ccc}-\cos \theta & -\sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1\end{array}\right]$$
B
$$\left[\begin{array}{ccc}\cos \theta & \sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1\end{array}\right]$$
C
$$\left[\begin{array}{ccc}\cos \theta & \sin \theta & 0 \\ -\sin \theta & \cos \theta & 0 \\ 0 & 0 & 1\end{array}\right]$$
D
$$\left[\begin{array}{ccc}\cos \theta & -\sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1\end{array}\right]$$
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