1
MHT CET 2023 9th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$A=\left[\begin{array}{cc}2 & -1 \\ -1 & 3\end{array}\right]$$, then the inverse of $$\left(2 A^2+5 A\right)$$ is

A
$$\frac{1}{95}\left[\begin{array}{ll}7 & 3 \\ 3 & 4\end{array}\right]$$
B
$$\frac{1}{95}\left[\begin{array}{cc}-7 & 3 \\ 3 & -4\end{array}\right]$$
C
$$\frac{1}{95}\left[\begin{array}{cc}-7 & -3 \\ 3 & 4\end{array}\right]$$
D
$$\frac{1}{95}\left[\begin{array}{ll}4 & 3 \\ 3 & 7\end{array}\right]$$
2
MHT CET 2021 21th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$A=\left[\begin{array}{ccc}\cos \theta & -\sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1\end{array}\right]$$, then $$\operatorname{adj} A=$$

A
$$\left[\begin{array}{ccc}-\cos \theta & -\sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1\end{array}\right]$$
B
$$\left[\begin{array}{ccc}\cos \theta & \sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1\end{array}\right]$$
C
$$\left[\begin{array}{ccc}\cos \theta & \sin \theta & 0 \\ -\sin \theta & \cos \theta & 0 \\ 0 & 0 & 1\end{array}\right]$$
D
$$\left[\begin{array}{ccc}\cos \theta & -\sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1\end{array}\right]$$
3
MHT CET 2021 21th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$A=\left[\begin{array}{lll}0 & 1 & 2 \\ 1 & 2 & 3 \\ 3 & a & 1\end{array}\right]$$ and $$A^{-1}=\frac{1}{2}\left[\begin{array}{ccc}1 & -1 & 1 \\ -8 & 6 & 2 c \\ 5 & -3 & 1\end{array}\right]$$, then values of a and c are respectively

A
$$\frac{1}{2}, \frac{1}{2}$$
B
$$-1,1$$
C
$$2, \frac{-1}{2}$$
D
$$1,-1$$
4
MHT CET 2021 21th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$A=\left[\begin{array}{lll}0 & 1 & 2 \\ 1 & 2 & 3 \\ 3 & 1 & 1\end{array}\right]$$, then $$A^{-1}=$$

A
$$\left(\frac{1}{2}\right)\left[\begin{array}{lll}0 & 1 & 2 \\ 3 & 2 & 1 \\ 4 & 2 & 3\end{array}\right]$$
B
$$\left[\begin{array}{ccc}\frac{1}{2} & \frac{-1}{2} & \frac{1}{2} \\ -4 & 3 & -1 \\ \frac{5}{2} & \frac{-3}{2} & \frac{1}{2}\end{array}\right]$$
C
$$\left[\begin{array}{ccc}\frac{1}{2} & -1 & \frac{5}{2} \\ 1 & -6 & 3 \\ 1 & 2 & -1\end{array}\right]$$
D
$$\left(\frac{1}{2}\right)\left[\begin{array}{ccc}1 & -1 & -1 \\ -8 & 6 & -2 \\ 5 & -3 & 1\end{array}\right]$$
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