1
MHT CET 2025 25th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a single slit diffraction experiment, slit of width ' $a$ ' is illuminated by light of wavelength ' $\lambda$ ' and the width of the central maxima in diffraction pattern is measured as ' $y$ '. When half of the slit is covered and illuminated by light of wavelength (1.5) $\lambda$, the width of the central maximum in diffraction pattern becomes

A
$\frac{3}{2} y$
B
$\frac{2}{3} y$
C
$3 y$
D
$\frac{\mathrm{y}}{3}$
2
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
If the two sources of light emit waves of different amplitudes and interfere then
A
there is some intensity of light in the region of destructive interference.
B
fringe width is less.
C
brightness of fringes is less.
D
fringes disappear after short time.
3
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

In Fraunhofer diffraction pattern, slit width is 0.3 mm and screen is at 1.5 m away from the lens. If wavelength of light used is $4500 \mathop {\rm{A}}\limits^{\rm{o}}$, then the distance between the first minimum on either side of the central maximum is [ $\theta$ is small and measured in radian.]

A
1.5 mm
B
2.25 mm
C
3.25 mm
D
4.5 mm
4
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A single slit diffraction pattern is formed with light of wavelength $6384 \mathop {\rm{A}}\limits^{\rm{o}}$. The second secondary maximum for this wavelength coincides with the third secondary maximum in the pattern for light of wavelength ' $\lambda_0$ '. The value of ' $\lambda_0$ ' is
A
$4242 \mathop {\rm{A}}\limits^{\rm{o}}$
B
$4560 \mathop {\rm{A}}\limits^{\rm{o}}$
C
$5474 \mathop {\rm{A}}\limits^{\rm{o}}$
D
$6384 \mathop {\rm{A}}\limits^{\rm{o}}$
MHT CET Subjects
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