If $[x]^2-5[x]+6=0$, where $[\cdot]$ denotes the greatest integer function, then

Let $\mathrm{f}(x)=(x+1)^2-1, x \geqslant-1$, then the set $\left\{x / f(x)=f^{-1}(x)\right\}$ is

If $\mathrm{f}:[1, \infty) \rightarrow[2, \infty)$ is given by $\mathrm{f}(x)=x+\frac{1}{x}$ then $\mathrm{f}^{-1}(x)$ equals

If $[x]^2-5[x]+6=0$, where $[x]$ denotes the greatest integer function, then