1
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
Let $f(x) = ax + b$ and $g(x) = cx + d$. The condition $f(g(x)) = g(f(x))$ holds for all $x$ if and only if ...
A
$f(a) = f(c)$
B
$f(b) = g(b)$
C
$f(d) = g(b)$
D
$f(c) = g(a)$
2
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $f(x) = \dfrac{1 - x}{1 + x}$, then $f(f(\cos x)) =$
A
$\cos x$
B
$x$
C
$\tan\dfrac{x}{2}$
D
$\cos\dfrac{x}{2}$
3
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $f(x) = \dfrac{x+2}{x^2-3x+1}$, then the values of $x$ for which $f(x)$ is not defined are
A
$x = \dfrac{3+\sqrt{5}}{2},\ x = \dfrac{3-\sqrt{5}}{2}$
B
$x = \dfrac{-3+\sqrt{5}}{2},\ x = \dfrac{-3-\sqrt{5}}{2}$
C
$x = \dfrac{3+\sqrt{3}}{2},\ x = \dfrac{3-\sqrt{3}}{2}$
D
$x = \dfrac{2+\sqrt{5}}{2},\ x = \dfrac{2-\sqrt{5}}{2}$
4
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $f : R \to R$ and $g : R \to R$ are defined as $f(x) = 2x - |x|$ and $g(x) = 2x + |x|$, then
A
$(fog)(2) + (gof)(2) = 0$
B
$(fog)(2) - (gof)(-2) = 0$
C
$(fog)(2) - (fog)(-2) = 0$
D
$(gof)(2) + (gof)(-2) = 0$

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