1
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $f(x) = \dfrac{x+2}{x^2-3x+1}$, then the values of $x$ for which $f(x)$ is not defined are
A
$x = \dfrac{3+\sqrt{5}}{2},\ x = \dfrac{3-\sqrt{5}}{2}$
B
$x = \dfrac{-3+\sqrt{5}}{2},\ x = \dfrac{-3-\sqrt{5}}{2}$
C
$x = \dfrac{3+\sqrt{3}}{2},\ x = \dfrac{3-\sqrt{3}}{2}$
D
$x = \dfrac{2+\sqrt{5}}{2},\ x = \dfrac{2-\sqrt{5}}{2}$
2
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $f : R \to R$ and $g : R \to R$ are defined as $f(x) = 2x - |x|$ and $g(x) = 2x + |x|$, then
A
$(fog)(2) + (gof)(2) = 0$
B
$(fog)(2) - (gof)(-2) = 0$
C
$(fog)(2) - (fog)(-2) = 0$
D
$(gof)(2) + (gof)(-2) = 0$
3
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $e^x + e^{f(x)} = e$, then the domain of $f(x)$ is
A
$(1, \infty)$
B
$(-\infty, 1)$
C
$(-\infty, \infty)$
D
$(-\infty, 0)$
4
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $f(x) = \dfrac{4x + 3}{6x - 4}$, $x \neq \dfrac{2}{3}$ and $(\text{fof})(x) = g(x)$ where $g: \mathbb{R} - \left\{\dfrac{2}{3}\right\} \rightarrow \mathbb{R} - \left\{\dfrac{2}{3}\right\}$, then $(g\,o\,g\,o\,g\,o\,g\,o\,g)\,(3) =$
A
$3$
B
$\dfrac{1}{3}$
C
$3^5$
D
$\dfrac{1}{3^5}$

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