1
MHT CET 2024 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $\left(m_i, \frac{1}{m_i}\right), m_i>0, i=1,2,3,4$ are four distinct points on a circle, then the product $\mathrm{m}_1 \mathrm{~m}_2 \mathrm{~m}_3 \mathrm{~m}_4$ is equal to

A
$-1$
B
1
C
0
D
2
2
MHT CET 2023 14th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The centre of the circle whose radius is 3 units and touching internally the circle $$x^2+y^2-4 x-6 y-12=0$$ at the point $$(-1,-1)$$ is

A
$$\left(\frac{4}{5}, \frac{7}{5}\right)$$
B
$$\left(\frac{4}{5}, \frac{-7}{5}\right)$$
C
$$\left(\frac{-4}{5}, \frac{-7}{5}\right)$$
D
$$\left(\frac{-4}{5}, \frac{7}{5}\right)$$
3
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If the line $$x-2 y=\mathrm{m}(\mathrm{m} \in \mathrm{Z})$$ intersects the circle $$x^2+y^2=2 x+4 y$$ at two distinct points, then the number of possible values of $m$ are

A
8
B
9
C
10
D
11
4
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The abscissae of two points $$A$$ and $$B$$ are the roots of the equation $$x^2+2 a x-b^2=0$$ and their ordinates are roots of the equation $$y^2+2 p y-q^2=0$$. Then, the equation of the circle with $$A B$$ as diameter is given by

A
$$x^2+y^2-2 a x-2 p y+\left(b^2+q^2\right)=0$$
B
$$x^2+y^2-2 a x-2 p y-\left(b^2+q^2\right)=0$$
C
$$x^2+y^2+2 a x+2 p y+\left(b^2+q^2\right)=0$$
D
$$x^2+y^2+2 a x+2 p y-\left(b^2+q^2\right)=0$$
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