MHT CET 2024 16th May Morning Shift | Probability Question 5 | Mathematics

A random variable X takes the values $0,1,2,3$ and its mean is 1.3 . If $\mathrm{P}(\mathrm{X}=3)=2 \mathrm{P}(\mathrm{X}=1)$ and $P(X=2)=0.3$, then $P(X=0)$ is

0.2

0.1

0.3

0.4

MHT CET 2024 16th May Morning Shift

MCQ (Single Correct Answer)

-0

Three persons $\mathrm{P}, \mathrm{Q}$ and R independently try to hit a target. If the probabilities of their hitting the target are $\frac{3}{4}, \frac{1}{2}$ and $\frac{5}{8}$ respectively, then the probability that the target is hit by P or Q but not by $R$, is

$\frac{15}{64}$

$\frac{21}{64}$

$\frac{39}{64}$

$\frac{9}{64}$

MHT CET 2024 16th May Morning Shift

MCQ (Single Correct Answer)

-0

A box contains 15 green and 10 yellow balls. If 10 balls are randomly drawn, one by one, with replacement, then the variance of the number of green balls drawn is

$6$

$4$

$\frac{6}{25}$

$\frac{12}{5}$

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

Suppose three coins are tossed simultaneously. If $X$ denotes the number of heads, then probability distribution of x is

$X=x$	0	1	2	3
$P(X=x)$	$\frac{2}{8}$	$\frac{2}{8}$	$\frac{3}{8}$	$\frac{1}{8}$

$X=x$	0	1	2	3
$P(X=x)$	$\frac{1}{8}$	$\frac{3}{8}$	$\frac{3}{8}$	$\frac{1}{8}$

$X=x$	0	1	2
$P(X=x)$	$\frac{3}{8}$	$\frac{3}{8}$	$\frac{2}{8}$

$X=x$	0	1	2	3
$P(X=x)$	$\frac{1}{8}$	$\frac{1}{8}$	$\frac{3}{8}$	$\frac{3}{8}$

PREVIOUS NEXT

MHT CET Subjects