MHT CET 2020 16th October Evening Shift | Circular Motion Question 33 | Physics

A particle of mass $$m$$ is performing UCM along a circle of radius $$r$$. The relation between centripetal acceleration $$a$$ and kinetic energy $$E$$ is given by

$$a=\frac{2 E}{m r}$$

$$a=2 E m$$

$$a=\frac{E}{m r}$$

$$a=\left(\frac{2 E}{m r}\right)^2$$

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

In non-uniform circular motion, the ratio of tangential to radial acceleration is ($$r=$$ radius, $$\alpha=$$ angular acceleration and $$v=$$ linear velocity)

$$\frac{r \alpha}{v}$$

$$\frac{v^2}{r a}$$

$$\frac{r \alpha^2}{v^2}$$

$$\frac{r^2 \alpha}{v^2}$$

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

A particle is moving in a radius $$R$$ with constant speed $$v$$. The magnitude of average acceleration after half revolution is

$$\frac{2 \pi}{R v^2}$$

$$\frac{2 R}{\pi v}$$

$$\frac{2 v^2}{\pi R}$$

$$\frac{2 V}{\pi R^2}$$

MHT CET 2019 3rd May Morning Shift

MCQ (Single Correct Answer)

-0

A mass is whirled in a circular path with constant angular velocity and its linear velocity is $v$. If the string is now halved keeping the angular momentum same, the linear velocity is

$2 v$

$\frac{v}{2}$

$v$

$v \sqrt{2}$

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