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1
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
$\int\dfrac{\log x}{(1 + \log x)^2}dx =$
A
$\dfrac{1}{1 + \log x} + c$
B
$-\dfrac{1}{1 + \log x} + c$
C
$\dfrac{x}{1 + \log x} + c$
D
$-\dfrac{x}{1 + \log x} + c$
2
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
$\int\dfrac{1}{\sqrt{2x - x^2}}dx =$
A
$\sin^{-1}(x - 1) + c$
B
$\cos^{-1}(x - 1) + c$
C
$\tan^{-1}(x - 1) + c$
D
$\sin^{-1}x + c$
3
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
$\int(x^{21} + x^6 + x^3)(2x^{18} + 7x^3 + 14)^{\frac{1}{3}}\ dx =$
A
$\dfrac{1}{56}(2x^{18} + 7x^3 + 14)^{\frac{4}{3}} + c$
B
$(2x^{18} + 7x^3 + 14)^{\frac{4}{3}} + c$
C
$(2x^{21} + 7x^6 + 14x^3)^{\frac{4}{3}} + c$
D
$\dfrac{1}{56}(2x^{21} + 7x^6 + 14x^3)^{\frac{4}{3}} + c$
4
MHT CET 2026 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $f(x) = \int \dfrac{x}{(x^2 + 4)(x^2 + 9)}\, dx$ and $f(0) = \dfrac{1}{5}\log\left(\dfrac{2}{3}\right)$, then $f(1) = $
A
$\dfrac{1}{5}\log(2)$
B
$\dfrac{1}{10}\log(2)$
C
$-\dfrac{1}{5}\log(2)$
D
$-\dfrac{1}{10}\log(2)$
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