1
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
Let $f(x) = 1 - \dfrac{1}{x}, g_2(x) = f(f(x)), g_3(x) = f(f(f(x)))$ and so on. If $\int x \cdot g_{2026}(x)\,dx = \int g_{2025}(x)\,dx + h(x) + c$, then $h(x) = $...
A
$x$
B
$-x$
C
$\log x$
D
$-\log x$
2
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The value of integral $\int x^3 \cos x\,dx$ is...
A
$x^3\sin x + x^2\cos x - 6x\sin x + 6\cos x + c$
B
$x^3\sin x + 3x^2\sin x - 6x\sin x - 6\cos x + c$
C
$x^3\sin x + 3x^2\cos x - 6x\sin x - 6\cos x + c$
D
$x^3\sin x + 3x^2\cos x - 6x\sin x + 6\cos x + c$
3
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $u$ and $v$ are functions of $x$, then $\int \dfrac{1}{v^3}\left(uv\dfrac{du}{dx} - u^2\dfrac{dv}{dx}\right)dx = $
A
$\log uv + c$
B
$\log\dfrac{u}{v} + c$
C
$\dfrac{v^2}{2u^2} + c$
D
$\dfrac{u^2}{2v^2} + c$
4
MHT CET 2026 19th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The value of integral $\displaystyle\int \dfrac{dx}{\sin^2 x + \tan^2 x}$ is...
A
$\dfrac{-1}{2\tan x} + \dfrac{1}{2\sqrt{2}}\tan^{-1}\left(\dfrac{\tan x}{\sqrt{2}}\right) + c$
B
$\dfrac{-1}{2\tan x} - \dfrac{1}{2\sqrt{2}}\tan^{-1}\left(\dfrac{\tan x}{\sqrt{2}}\right) + c$
C
$\dfrac{1}{2\tan x} - \dfrac{1}{2\sqrt{2}}\tan^{-1}\left(\dfrac{\tan x}{\sqrt{2}}\right) + c$
D
$\dfrac{1}{2\tan x} + \dfrac{1}{2\sqrt{2}}\tan^{-1}\left(\dfrac{\tan x}{\sqrt{2}}\right) + c$

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