1
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
$\displaystyle\int \dfrac{(x + 1)(x + \log x)^2}{x}\,dx =$
A
$\left(\dfrac{x + \log x}{x}\right)^2 + c$, where c is the constant of integration
B
$\dfrac{(x + \log x)^2}{x} + c$, where c is the constant of integration
C
$\dfrac{(x + \log x)^3}{3} + c$, where c is the constant of integration
D
$\dfrac{(x + \log x)^3}{3x} + c$, where c is the constant of integration
2
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
$\displaystyle\int \cot^4 x\,dx$ is equal to
A
$\dfrac{\cot^3 x}{3} - \cot x + x + c$
B
$\dfrac{\cot^3 x}{3} + \cot x + x + c$
C
$-\dfrac{\cot^3 x}{3} + \cot x + x + c$
D
$\dfrac{\cot^3 x}{3} - 2\cot x + x + c$
3
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
$\displaystyle\int \dfrac{\cos^3 x}{\sin^2 x + \sin x}\,dx =$
A
$\log(\cos x) + \cos x + c$, where c is the constant of integration
B
$\log(\sin x) - \sin x + c$, where c is the constant of integration
C
$\log(\sin x) + \sin x + c$, where c is the constant of integration
D
$\log(\cos x) - \cos x + c$, where c is the constant of integration
4
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
$\int \dfrac{x^2\, \text{d}x}{(x^2 + 2)(x^2 + 5)} =$
A
$-\left(\dfrac{\sqrt{2}}{3}\tan^{-1}\dfrac{x}{\sqrt{2}} + \dfrac{\sqrt{5}}{3}\tan^{-1}\dfrac{x}{\sqrt{5}}\right) + c$, where c is the constant of integration
B
$\left(\dfrac{\sqrt{2}}{3}\tan^{-1}\dfrac{x}{\sqrt{2}} + \dfrac{\sqrt{5}}{3}\tan^{-1}\dfrac{x}{\sqrt{5}}\right) + c$, where c is the constant of integration
C
$\dfrac{\sqrt{2}}{3}\tan^{-1}\left(\dfrac{x}{\sqrt{2}}\right) - \dfrac{\sqrt{5}}{3}\tan^{-1}\left(\dfrac{x}{\sqrt{5}}\right) + c$, where c is the constant of integration
D
$-\dfrac{\sqrt{2}}{3}\tan^{-1}\left(\dfrac{x}{\sqrt{2}}\right) + \dfrac{\sqrt{5}}{3}\tan^{-1}\left(\dfrac{x}{\sqrt{5}}\right) + c$, where c is the constant of integration

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