The value of $\int \frac{\mathrm{d} x}{x^2\left(x^4+1\right)^{\frac{3}{4}}}$ is

If $\int\left(\frac{4 e^x-25}{2 e^x-5}\right) d x=A x+B \log \left(2 e^x-5\right)+c \quad$ (where c is a constant of integration) then

$$\int \tan ^{-1}\left(\frac{1-\sin x}{1+\sin x}\right) d x=$$

$$\int \frac{\left(x^2+1\right)}{(x+1)^2} \mathrm{~d} x=$$