1
MHT CET 2026 19th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
In Young's double slit experiment, for the $n^{\text{th}}$ dark fringe ($n = 1, 2, 3, \ldots$) the phase difference of the interfering waves in radian will be
A
$n \cdot \dfrac{\pi}{2}$
B
$(2n + 1)\pi$
C
$(2n - 1)\pi$
D
$(2n - 1)\dfrac{\pi}{2}$
2
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
In a biprism experiment, fifth dark fringe is obtained at a point. A thin transparent film of refractive index '$\mu$' is placed in one of the interfering paths. Now $7^{th}$ bright fringe is obtained at the same point. If '$\lambda$' is the wavelength of light used, the thickness of film is equal to
A
$1.5(\mu - 1)\lambda$
B
$\dfrac{1.5\,\lambda}{(\mu-1)}$
C
$2.5(\mu - 1)\lambda$
D
$\dfrac{2.5\,\lambda}{(\mu-1)}$
3
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
A plane wavefront of width $x$, is incident on an air-water interface and the corresponding refracted wavefront has a width y as shown in figure. The refreactive index of air with respect to water in terms of distances w and z is
MHT CET 2026 18th April Evening Shift Physics - Wave Optics Question 20 English
A
$\dfrac{w}{z}$
B
$\dfrac{z}{w}$
C
$\sqrt{\dfrac{w}{z}}$
D
$\sqrt{\dfrac{z}{w}}$
4
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
In an optical instrument- microscope, the wavelength of light used are $\lambda_1 = 6800$ Å and $\lambda_2 = 5100$ Å. The ratio of the resolving power of microscope corresponding to '$\lambda_1$' to that for '$\lambda_2$' is
A
$9:16$
B
$5:4$
C
$4:3$
D
$3:4$

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