1
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If the lines $\vec{r} = \hat{i} + \hat{j} - \hat{k} + \lambda(q\hat{i} - 2\hat{j} + \hat{k})$ and $\vec{r} = p\hat{i} - 3\hat{j} + 2\hat{k} + \mu(\hat{i} - 2\hat{j} + 2\hat{k})$ intersect each other and $q\hat{i} - 2\hat{j} + \hat{k}$ is collinear to $4\hat{i} - 4\hat{j} + 2\hat{k}$, then the values of $p$ and $q$ are
A
$p = 4,\ q = 3$
B
$p = 2,\ q = 3$
C
$p = 4,\ q = 2$
D
$p = 4,\ q = 1$
2
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The angle between a diagonal and one of its edges of a cube is ...................
A
$\tan^{-1}\left(\dfrac{1}{\sqrt{2}}\right)$
B
$\cos^{-1}\left(\dfrac{1}{3}\right)$
C
$\cos^{-1}\left(\dfrac{1}{2\sqrt{2}}\right)$
D
$\tan^{-1}\left(\sqrt{2}\right)$
3
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The equation of a line in cartesian form passing through (0, 0, 0) and (4, 3, c) and parallel to $\vec{a} \times \vec{b}$ where $\vec{a} = 2\hat{i} + \hat{j} + 2\hat{k}$, $\vec{b} = 3\hat{i} - 4\hat{j}$ is
A
$\dfrac{x-4}{8} = \dfrac{y-3}{6} = \dfrac{z + \frac{11}{2}}{11}$
B
$\dfrac{x-4}{8} = \dfrac{y+3}{6} = \dfrac{z + \frac{11}{2}}{-11}$
C
$\dfrac{x-4}{8} = \dfrac{y-3}{6} = \dfrac{z + \frac{11}{2}}{-11}$
D
$\dfrac{x+4}{8} = \dfrac{y-3}{6} = \dfrac{z + \frac{11}{2}}{-11}$
4
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If the lines $2x = ky = -z$ and $6x = -y = -4z$ are perpendicular to each other then the value of $k$ is ...
A
$16$
B
$5$
C
$10$
D
$3$

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