1
MHT CET 2026 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If M denotes the midpoint of the line joining A$(4, 5, -10)$ and B$(-1, 2, 1)$, then the equation of the plane through M and perpendicular to AB is:
A
$\bar{r} \cdot \left(-5\hat{i} - 3\hat{j} + 11\hat{k}\right) + \dfrac{135}{2} = 0$
B
$\bar{r} \cdot \left(\dfrac{3}{2}\hat{i} + \dfrac{7}{2}\hat{j} - \dfrac{9}{2}\hat{k}\right) + \dfrac{135}{2} = 0$
C
$\bar{r} \cdot \left(4\hat{i} + 5\hat{j} - 10\hat{k}\right) + 4 = 0$
D
$\bar{r} \cdot \left(-\hat{i} + 2\hat{j} + \hat{k}\right) + 4 = 0$
2
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The perpendicular distance from the origin to the plane containing the points $(1, -2, 1), (2, -1, -3)$ and $(0, 1, 5)$ is...(in units)
A
$\dfrac{1}{\sqrt{17}}$
B
$\dfrac{3}{\sqrt{26}}$
C
$\dfrac{5}{\sqrt{17}}$
D
$\dfrac{7}{\sqrt{26}}$
3
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $\alpha, \beta, \gamma$ are the direction angles of the line $x = 4z + 3$ and $y = 2 - 3z$, then the value of $\cos\alpha + \cos\beta + \cos\gamma$ is...
A
$\dfrac{8}{\sqrt{26}}$
B
$\dfrac{6}{\sqrt{26}}$
C
$\dfrac{4}{\sqrt{26}}$
D
$\dfrac{2}{\sqrt{26}}$
4
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The shortest distance between the lines $\vec{r} = (4\hat{i} - \hat{j}) + \lambda(\hat{i} + 2\hat{j} - 3\hat{k})$ and $\vec{r} = (\hat{i} - \hat{j} + 2\hat{k}) + \mu(\hat{i} + 4\hat{j} - 5\hat{k})$ is...
A
$\dfrac{1}{\sqrt{2}}$
B
$\dfrac{1}{2}$
C
$\dfrac{1}{\sqrt{3}}$
D
$\dfrac{1}{3}$

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