1
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $A = [a_{ij}]_{3 \times 3}$ is a matrix such that $a_{ij} = |2i - 5j|$, where $|.|$ denotes the modulus function, then the element in the $2^{\text{nd}}$ row and $3^{\text{rd}}$ column of $A^{-1}$ is ...
A
$3$
B
$1$
C
$0$
D
$-1$
2
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $A = \begin{bmatrix} 2 & -1 \\ 0 & 2 \end{bmatrix}$ and $A^2 + xA + yI_2 = O_2$, where $I_2$ and $O_2$ are the identity matrix and null matrix of order 2 respectively, then:
A
$x = 4,\ y = 4$
B
$x = -4,\ y = 4$
C
$x = -4,\ y = -2$
D
$x = 4,\ y = -4$
3
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
Inverse of $\begin{bmatrix} 3 & -2 \\ 1 & 4 \end{bmatrix}$ is
A
$\begin{bmatrix} \dfrac{2}{7} & \dfrac{1}{7} \\ -\dfrac{1}{14} & \dfrac{3}{14} \end{bmatrix}$
B
$\begin{bmatrix} \dfrac{3}{14} & -\dfrac{1}{7} \\ \dfrac{1}{14} & \dfrac{2}{7} \end{bmatrix}$
C
$\begin{bmatrix} \dfrac{2}{7} & -\dfrac{1}{7} \\ \dfrac{1}{14} & \dfrac{3}{14} \end{bmatrix}$
D
$\begin{bmatrix} -\dfrac{3}{14} & \dfrac{1}{7} \\ \dfrac{1}{14} & \dfrac{2}{7} \end{bmatrix}$
4
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $A = \begin{bmatrix} 5a & -b \\ 3 & 2 \end{bmatrix}$ and $A\,(\text{adj }A) = AA^T$, Then $5a + b =$
A
$2$
B
$3$
C
$5$
D
$\dfrac{15}{2}$

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