MHT CET 2026 17th April Evening Shift | Rotational Motion Question 16 | Physics

A mass tied to a string is whirled in a horizontal circular path with a constant angular velocity and its angular momentum is 'L'. If the length of the string is now halved, keeping angular velocity same then the angular momentum will be

$\dfrac{L}{4}$

$\dfrac{L}{2}$

$L$

$2L$

MHT CET 2026 17th April Morning Shift

MCQ (Single Correct Answer)

-0

Four point masses m, 2m, 3m and 4m are kept at the corners A, B, C and D respectively of a square ABCD of side '$b$'. The moment of inertia of the system about an axis perpendicular to the plane of the square and passing through the point D is

$12\ mb^2$

$10\ mb^2$

$8\ mb^2$

$5\ mb^2$

MHT CET 2026 17th April Morning Shift

MCQ (Single Correct Answer)

-0

A system of five solid spheres each of mass '$m$' and radius '$r$' are rotating about an axis AA' as shown in figure. Hence the moment of inertia of the system about the axis of rotation AA' is
MHT CET 2026 17th April Morning Shift Physics - Rotational Motion Question 17 English

MHT CET 2026 17th April Morning Shift Physics - Rotational Motion Question 17 English

$6\ mr^2$

$5\ mr^2$

$4\ mr^2$

$3\ mr^2$

MHT CET 2026 17th April Morning Shift

MCQ (Single Correct Answer)

-0

Two bodies A and B have moment of inertia $I_A$ and $I_B$, and angular momenta $L_A$ and $L_B$ respectively. Both of them have same kinetic energy of rotation. So the ratio $L_A$ to $L_B$ is

$\dfrac{I_A}{I_B}$

$\dfrac{I_A^2}{I_B^2}$

$\sqrt{\dfrac{I_A}{I_B}}$

$\sqrt{\dfrac{I_B}{I_A}}$

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