1
MHT CET 2026 11th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A flywheel rotating about a fixed axis has a kinetic energy of $500$ joule, if its angular frequency is $5$ Hz, then calculate the moment of inertia of the wheel about the axis of rotation. ($\pi^2=10$)
A
$0.6 \text{ kg m}^2$
B
$1 \text{ kg m}^2$
C
$0.75 \text{ kg m}^2$
D
$0.15 \text{ kg m}^2$
2
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The angular momentum of a rotating body is ' $L$ '. When the frequency of rotating body is tripled and its kinetic energy is made one-third, the new angular momentum becomes

A

$\frac{1}{9} \mathrm{~L}$

B

$\frac{1}{3} \mathrm{~L}$

C

6 L

D

9 L

3
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The moment of inertia of a thin uniform rod of mass ' $M$ ' and length ' $L$ ', about an axis perpendicular to length of the rod and at a distance ' $L / 4$ ' from one end is

A

$\frac{\mathrm{ML}^2}{6}$

B

$\frac{\mathrm{ML}^2}{12}$

C

$\frac{7 \mathrm{ML}^2}{24}$

D

$\frac{7 \mathrm{ML}^2}{48}$

4
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

A same torque is applied to a disc and a ring of equal mass and radii then

A
the ring will rotate with greater angular frequency.
B
both will rotate with same angular frequency.
C
the disc will rotate with greater angular frequency.
D
both will rotate with same angular velocity.

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